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发表于 2018-10-21 20:11:37
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搞明白了怎么显示了,先写个显示的demo显示数字0,为了便于仿真,不停输出,实际使用的时候,是可以锁在的,不改变数字时,不用写入,然后再用proteus仿真一下,因为proteus里没有SAA1060这个元件,要不可直接看数码管显示,现在只能看虚拟仪器里的时序了,代码附后,代码写得效率可能不是很好,但看仿真的结果应该是没有问题。& Q* y- j4 b1 n% G @
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demo 的代码在这里
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#include "reg52.h" //此文件中定义了单片机的一些特殊功能寄存器
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sbit yData = P2^0;& [/ R; D H6 P* N/ p- a$ L0 l. I8 e
sbit yDLEN = P2^2;
; v) U+ ?/ k6 q. csbit yCLK = P2^1;
1 _9 y3 H* G- Y' wconst int dailyCount = 200;# G6 @: U* O* ~8 T, a2 \; L
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void delay(unsigned int i) f% z$ n9 M# S, n" f8 q
{
( {5 B1 e; {* T* G2 r while(i--);
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void disp(unsigned int num )
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unsigned char i ;# N; p! T. Q6 A$ Z
6 n6 y# \# G( A8 V: _: h unsigned char dispA[20];: S% S- v8 X8 ^- A* `0 @' M
unsigned char dispB[20];% F9 s: F9 v- ]# z; V8 d
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unsigned char num1;7 y9 o; t% ]( W- f
unsigned char num2; - O) q$ [" d# B; \! X5 `+ X" Z
unsigned char num3;7 d8 f8 E* r y( z' m' L6 D4 C- ~
unsigned char num4;
2 y3 B+ {% Y' D0 L$ Y9 n0 Q+ G unsigned char segR[10] ; //右0 T% M4 p7 F# k; K2 d
unsigned char segL[10]; //左: `6 q7 N; t# f% {
$ T/ t, o& B+ j! N' X //左
1 ?$ f4 q8 \7 P0 ^) E segL[0] = 0x12;1 Q: r2 a. X6 D% D* T
segL[1] = 0xFA;
% R1 ^, j5 O; Q! ~% d( H3 ^# X: C segL[2] = 0x0E;
- _( `* F5 n% @- K) n2 x6 x. [$ _ segL[3] = 0x2A;
8 V- W$ L0 I* U) P) }5 s segL[4] = 0xE2; _+ z" |7 ?: A4 j
segL[5] = 0x63;
4 c* I! a2 V( \: t; Z segL[6] = 0x2A;
7 c( l) |% v5 O( i% L( z segL[7] = 0x7A; O8 s T6 d% r8 Y Y9 I' y
segL[8] = 0x02;- |) J y+ r! R& V
segL[9] = 0x22;
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//右; s t) {2 |+ {9 n8 X/ _. r
segR[0] = 0x88;
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9 R* J# e) ]- |+ d, j segR[2] = 0x85;3 v6 t1 L7 \3 W: l( c* M
segR[3] = 0x83;; `5 R; T3 E( F( h" F; ?) X
segR[4] = 0xE2;$ x+ \- q. {1 ]1 u4 S( ]
segR[5] = 0x92;
2 I8 i2 l3 a" [( G segR[6] = 0x90;
) L4 q9 H% Z0 W0 Q0 i segR[7] = 0xCB;) b5 t3 H4 I: I' o) q$ u9 y& M
segR[8] = 0x80;
4 }# S' N1 S# N- [' ^ segR[9] = 0x82;4 A: J/ @6 J( i, c7 M& J
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/ H0 d x$ H! e% k- c num1=num /1000;) p! B; P# V" p3 R# P2 @6 C/ M% M p
num2=(num /100)%10;;$ }- D5 n, b% T# o2 v
num3=(num /10)%100;;;
( @! q5 }7 Q% Q: q9 }( i/ E num4=num%10;
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" J" {& u6 h* z# h) N. j8 B dispA[0] = 0;1 a& h, d* X+ u3 V
dispB[0] = 0;8 d/ c# ?( c% \- b, { `! y
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for (i=0;i<8;i++). k0 _6 G. J& a$ c0 S( g0 i4 C( Q
{
2 @. W. U+ \% K6 Y4 \ _" r) _ dispA[i+1] = (segR[num2]>>i)&0x01;
8 b/ z1 z. |2 W1 v$ o dispB[i+1] = (segR[num1]>>i)&0x01;
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dispA[i+9] = (segL[num4]>>i)&0x01;2 x; P" T E; W/ o5 g
dispB[i+9] = (segL[num3]>>i)&0x01;$ ~4 \$ n0 X+ I% n
}
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4 l4 c- [9 s Y6 X, S dispA[17] = 1;" Z6 M N. A3 ?7 _6 A" M* M- b
dispB[17] = 0;1 E @" x3 X6 E; h1 c. ?" u
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dispA[18] = 0;
# Y0 U1 }- y& J6 v dispB[18] = 0;6 E h$ j2 I5 G* l
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dispA[19] = 0;
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9 t2 m( b& ` n( Y' h1 A2 O# q yCLK = 1;+ \+ C$ H2 \* z y" }) f
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yCLK = 1;8 M) n1 F" _$ ?3 P9 f2 C& K/ ^
yData = dispA;2 @$ r, J/ C% g# S- j; `
delay(2);5 N z2 [1 [- s; w
if(i>17)
o! O' }9 z; k" i3 A {yDLEN=0;}2 t- L0 z4 k3 d! i- S8 |* U: L
else
" _! h1 |' h/ J6 Q {8 \+ u, o {yDLEN=1;}9 G" w" x6 Y2 h* G, l8 X0 k
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delay(dailyCount);
- P5 f0 A0 D' ]0 Y5 v yCLK = 0 ;
: \" v6 \/ I7 t delay(dailyCount);
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# ~# [+ x- ^% Q: o yCLK=0;5 W3 `7 B7 i& B4 ?% }# O
yData=0;7 a i& S8 h7 |+ L' J0 T/ I: ?0 v
yDLEN=0;
5 d" ?- b. q: {0 y. s. ~' T delay(dailyCount*10);4 c7 w+ [% o* m
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{
1 X! e- i1 [2 P# z( F9 a9 R6 w6 E, r yCLK = 1;, Z' h9 R$ ^+ ?; {5 |" ~$ H& V
yData = dispB;
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{yDLEN=0;}! F4 m& {' s5 E+ m* X3 `6 e
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{yDLEN=1;}
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yCLK = 0 ;; c, T9 m" i: @+ H# q# P
delay(dailyCount);" }! c9 t/ G& u2 U6 f% f5 ~
}
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yCLK=0;
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yDLEN=0;6 j# ~" ?9 @9 a9 }% F) B
delay(dailyCount*10);
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void main()
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while(1)
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delay(4000);
% F2 h5 I+ q# f8 }; O5 r disp(0);
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