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楼主 |
发表于 2018-10-21 20:11:37
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搞明白了怎么显示了,先写个显示的demo显示数字0,为了便于仿真,不停输出,实际使用的时候,是可以锁在的,不改变数字时,不用写入,然后再用proteus仿真一下,因为proteus里没有SAA1060这个元件,要不可直接看数码管显示,现在只能看虚拟仪器里的时序了,代码附后,代码写得效率可能不是很好,但看仿真的结果应该是没有问题。! {# o5 V2 \/ X% ]
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0 y- V8 r0 G7 |& ]1 @demo 的代码在这里! I1 G- j4 f2 l
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#include "reg52.h" //此文件中定义了单片机的一些特殊功能寄存器4 l D1 N' Z v- @1 i& F
* \ U9 m8 d; j) Msbit yData = P2^0;
+ t0 H# u& T) Q( H7 S$ ~sbit yDLEN = P2^2;
* ^7 @( n7 y( v/ m0 Y# C1 asbit yCLK = P2^1;
N" c8 z5 D5 O/ q' ^2 n" A5 Cconst int dailyCount = 200;
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void delay(unsigned int i)
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$ ^0 [% K% Z* d1 i while(i--);
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void disp(unsigned int num )
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( G. R7 I/ v) s I& y unsigned char i ;9 U: N, e) T1 w
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unsigned char dispA[20];
3 O& A8 v2 z2 m, d1 M f& J& C unsigned char dispB[20];# V0 F% Z9 t3 G1 x0 T5 C5 h l
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unsigned char num1;
( f& H1 l; N8 o. z5 g unsigned char num2;
" v( z1 I* l0 E. A$ X8 w+ N1 n unsigned char num3;+ J5 w; M) h$ g1 I0 ]) j0 V
unsigned char num4;3 o; r& k3 Y6 e2 Z+ e& G4 B
unsigned char segR[10] ; //右
' J G* u/ |9 P9 D, q unsigned char segL[10]; //左. ]2 t* X2 q- Y
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//左
8 _: }6 z6 R3 N' E3 |- p, M& G segL[0] = 0x12;
; j9 [7 E; x2 A segL[1] = 0xFA;
. W& i2 a0 k. k# @$ @2 s segL[2] = 0x0E;
* r3 D3 U6 ?! I, ]3 t* f3 ~! a: R segL[3] = 0x2A;( C+ D; D- _" v
segL[4] = 0xE2;
. [$ a4 k8 Z1 W: N1 U: h+ u* P segL[5] = 0x63;
' `4 ?: i5 L, S! p6 m! @ segL[6] = 0x2A;" g+ C9 ^0 A+ b- v& Z9 X0 R' ~
segL[7] = 0x7A;9 f* E1 F% c* i5 U, R. i
segL[8] = 0x02;+ W& T( M. c0 q
segL[9] = 0x22;- [$ l& X2 ~5 J o
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//右0 |/ |* X* s; A* y8 q
segR[0] = 0x88;9 M* U; }) B, [+ E7 m/ Q0 L9 s4 N
segR[1] = 0xEB;
2 v& X7 R/ l# V6 `5 k1 P; Z2 s segR[2] = 0x85;, K# ]( [& q" O v# K4 a
segR[3] = 0x83;
- P+ V- h" f0 Z5 R1 u( b5 V( C segR[4] = 0xE2;
9 B) }6 S4 y, i2 G; ?2 R5 y segR[5] = 0x92;
/ o5 a1 z* D1 m9 h9 I* l segR[6] = 0x90;
$ X. B/ B$ Y$ W% @ q segR[7] = 0xCB;
; L! X6 o1 j1 S8 _, V+ P segR[8] = 0x80;
) f: Z, ~7 [- b. z segR[9] = 0x82;1 E9 Q5 H8 W0 K
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6 g2 T: V3 p" N: \* U& j' x8 n, w6 |. O num1=num /1000;5 ]7 Z `$ p( \5 B: H% v
num2=(num /100)%10;;
( O" @! E7 o( K! r9 Z8 j# u7 o num3=(num /10)%100;;;
1 ^+ m& _* M3 H/ D num4=num%10;0 W( F9 f6 S8 k/ Y4 ~
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dispB[0] = 0;
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for (i=0;i<8;i++)* A1 t: c2 u, n$ e4 f" `7 M0 N
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dispA[i+1] = (segR[num2]>>i)&0x01;7 ^: S2 g) G8 N
dispB[i+1] = (segR[num1]>>i)&0x01; : t; K: J1 T& x6 R5 o9 @: v6 |
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dispA[i+9] = (segL[num4]>>i)&0x01;
: m) B. j: O1 }* z1 Q7 r! D dispB[i+9] = (segL[num3]>>i)&0x01;
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3 {, ?. K5 i; n- k$ g7 C, t/ h4 d dispA[17] = 1;
% t& v6 t! z' u, x4 } dispB[17] = 0; E0 W$ z) i1 ~% r, {/ U' i$ X# }) _
) q8 ?6 k0 g3 ]2 ?, m dispA[18] = 0;
! Y( O) X5 g3 ]3 P8 B6 O dispB[18] = 0;
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dispA[19] = 0;
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yCLK = 1;
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for (i = 0;i<20;i++). m- ~& U ^# L8 c+ X
{
* m* J2 O w$ @# f yCLK = 1;
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delay(2);- d8 I1 e6 V* R' W& E
if(i>17)$ q+ h' @4 w, e( Z6 y6 m
{yDLEN=0;}) _$ X! Q9 T: _# X! n
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{yDLEN=1;} X+ L$ G$ s9 ?) w; H
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- \- M+ R8 @0 V& w z' W yCLK = 0 ;7 O w7 h2 D" G+ n) G
delay(dailyCount);
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yCLK=0; n0 R% d) {& F; ]- j6 {) f' i; s
yData=0;, g# T* x6 c$ P9 o
yDLEN=0;
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+ H# f. B& k: P3 c1 G1 E yCLK = 1;' p) c% F8 F9 b' ^, r
yData = dispB;
+ f9 [- l1 A" J m8 [1 R# v e6 ? delay(dailyCount/10);
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' ]! V4 ~; T6 F- ` {yDLEN=0;}; ~( h2 Q/ B% s6 g8 N, u, W
else
3 V# B% L, a9 B {yDLEN=1;}0 x8 m. S1 \2 D. o/ v
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3 Z% r2 ^' v; ?0 ~ yCLK = 0 ;
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* S' c6 Y( |. p4 ]- F* _% s. D yCLK=0;
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yDLEN=0;3 n% Y, D% q$ U# N) U' O1 s
delay(dailyCount*10);
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void main()7 A, J) H( ] f [ N
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while(1)
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# b7 b; f# j6 P! X3 _' H delay(4000);
& {4 s4 z/ g: q$ A, U" y" o disp(0);/ d' z9 q5 l/ y& q
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